题目
You are given a string s containing lowercase English letters, and a matrix shift, where shift[i] = [direction, amount]:
- direction can be 0 (for left shift) or 1 (for right shift).
- amount is the amount by which string s is to be shifted.
- A left shift by 1 means remove the first character of s and append it to the end.
- Similarly, a right shift by 1 means remove the last character of s and add it to the beginning.
Return the final string after all operations.
解题思路
代码
class Solution:
def stringShift(self, s: str, shift: List[List[int]]) -> str:
final_shift = 0
for direction, amount in shift:
if direction:
final_shift += amount
else:
final_shift -= amount
final_shift %= len(s)
return s[-final_shift:] + s[:-final_shift]
