LeetCode 528 Random Pick with Weight (Python)

Posted by 小明MaxMing on June 5, 2020

题目

Given an array w of positive integers, where w[i] describes the weight of index i, write a function pickIndex which randomly picks an index in proportion to its weight.

Note:

  1. 1 <= w.length <= 10000
  2. 1 <= w[i] <= 10^5
  3. pickIndex will be called at most 10000 times.

解题思路

求石头重量的部分和,随机0到总和之间的一个随机数,二分搜索这个随机数的位置

代码

import random
import bisect
class Solution:

    def __init__(self, w: List[int]):
        self.sum = [w[0]]
        for n in w[1:]:
            self.sum.append(self.sum[-1] + n)

    def pickIndex(self) -> int:
        # def search(n):
        #     l, r = 0, len(self.sum)    
        #     while l < r:
        #         m = (l + r) // 2
        #         if self.sum[m] <= n:
        #             l = m + 1
        #         else:
        #             r = m
        #     return l
        # num = random.randint(0, self.sum[-1] - 1)
        # return search(num)
        # return bisect.bisect(self.sum, num)
        return bisect.bisect(self.sum, self.sum[-1] * random.random())

# Your Solution object will be instantiated and called as such:
# obj = Solution(w)
# param_1 = obj.pickIndex()

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