DP

LeetCode 198 House Robber (Python)

Posted by 小明MaxMing on September 14, 2020

题目

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

解题思路

dp[i]表示打劫到第i个房子,最多能抢多少钱,dp[n]为所求
dp[i] = max(dp[i - 2] + nums[i], dp[i - 1])
dp[0] = nums[0]
dp[1] = max(nums[0], nums[1])

代码

class Solution:
    def rob(self, nums: List[int]) -> int:
        dp0 = dp1 = 0
        for i in range(len(nums)):
            dp0, dp1 = dp1, max(dp0 + nums[i], dp1)
        return dp1

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