LeetCode 966 Vowel Spellchecker (Python)

Posted by 小明MaxMing on March 22, 2021

题目

Given a wordlist, we want to implement a spellchecker that converts a query word into a correct word.

For a given query word, the spell checker handles two categories of spelling mistakes:

  • Capitalization: If the query matches a word in the wordlist (case-insensitive), then the query word is returned with the same case as the case in the wordlist.
    • Example: wordlist = [“yellow”], query = “YellOw”: correct = “yellow”
    • Example: wordlist = [“Yellow”], query = “yellow”: correct = “Yellow”
    • Example: wordlist = [“yellow”], query = “yellow”: correct = “yellow”
  • Vowel Errors: If after replacing the vowels (‘a’, ‘e’, ‘i’, ‘o’, ‘u’) of the query word with any vowel individually, it matches a word in the wordlist (case-insensitive), then the query word is returned with the same case as the match in the wordlist.
    • Example: wordlist = [“YellOw”], query = “yollow”: correct = “YellOw”
    • Example: wordlist = [“YellOw”], query = “yeellow”: correct = “” (no match)
    • Example: wordlist = [“YellOw”], query = “yllw”: correct = “” (no match) In addition, the spell checker operates under the following precedence rules:
  • When the query exactly matches a word in the wordlist (case-sensitive), you should return the same word back.
  • When the query matches a word up to capitlization, you should return the first such match in the wordlist.
  • When the query matches a word up to vowel errors, you should return the first such match in the wordlist.
  • If the query has no matches in the wordlist, you should return the empty string. Given some queries, return a list of words answer, where answer[i] is the correct word for query = queries[i].

解题思路

使用两个字典存变成小写以及替换所有元音字母后的形式(把所有元音字母变成#

代码

class Solution:
    def spellchecker(self, wordlist: List[str], queries: List[str]) -> List[str]:
        wordset = set(wordlist)
        capdict = {}
        voweldict = {}
        for w in wordlist:
            lower = w.lower()
            if lower not in capdict:
                capdict[lower] = w
            tmp = ''.join(['#' if c in 'aeiou' else c for c in lower])
            if tmp not in voweldict:
                voweldict[tmp] = w
        res = []
        for q in queries:
            if q in wordset:
                res.append(q)
                continue
            lower = q.lower()
            if lower in capdict:
                res.append(capdict[lower])
                continue
            tmp = ''.join(['#' if c in 'aeiou' else c for c in lower])
            if tmp in voweldict:
                res.append(voweldict[tmp])
                continue
            res.append("")
        return res

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