题目
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: “a” maps to “.-“, “b” maps to “-…”, “c” maps to “-.-.”, and so on.
For convenience, the full table for the 26 letters of the English alphabet is given below:
Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cab" can be written as "-.-..--...", (which is the concatenation "-.-." + ".-" + "-..."). We'll call such a concatenation, the transformation of a word.
Return the number of different transformations among all words we have.
### 解题思路
将字符串转换成morse code，然后放到一个set中，返回长度
### 代码
```python
class Solution:
def uniqueMorseRepresentations(self, words: List[str]) -> int:
morse = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
translate = {''.join([morse[ord(c)-97] for c in word]) for word in words}
return len(translate)
